Coax TEM Mode Calculator

The Coax TEM Mode Calculator (Coax Calculator) provides engineers with an online tool to analyze Coax  Configurations for their circuits.  The Coax TEM Mode Calculator (Coax Calculator) is used to determine the TEM Mode guided wave properties in a Coax Transmission Line for the dimensions and material properties defined by the user.

The Coax TEM Mode Calculator (Coax Calculator) determines following characteristics of a Coax TEM Mode:

  1. 1Cutoff Frequency for the Coax TE1,1 mode.
  2. 2Coax TEM Mode Characteristic Impedance.
  3. 3Coax TEM Mode Guide Wavelength.
  4. 4Coax TEM Mode Propagation Constant.
  5. 5Coax TEM Mode Phase Velocity.
  6. 6Coax TEM Mode Group Velocity.
  7. 7Coax TEM Mode Attenuation Constant due to Metal and Dielectric Loss.

Tutorial · RF & Microwave Transmission Lines

Coaxial TEM Mode Calculator Tutorial

This tutorial walks through a complete analysis of a coaxial waveguide geometry with the SiberSci Coax TEM Mode Calculator. Using an SMA-size, PTFE-filled copper line at 10 GHz, each step shows what to enter, what the calculator returns, and the equation behind the result so the number can be checked by hand.

Open the Coax TEM Mode Calculator

1. What the Coax TEM Mode Calculator computes

A coaxial line supports a transverse electromagnetic (TEM) mode with no cutoff frequency. Given the conductor dimensions, the dielectric fill, the conductor metal, and the operating frequency, the calculator returns seven properties of that TEM mode:

  1. TE1,1 cutoff frequency — the upper frequency limit for single-mode (TEM-only) operation.
  2. Characteristic impedance Z0 in ohms.
  3. Guide wavelength λg.
  4. Propagation constant γ=α+jβ.
  5. Phase velocity vp.
  6. Group velocity vg.
  7. Attenuation constant from conductor (metal) loss αc and dielectric loss αd.

The equations below assume a non-magnetic dielectric (μr=1), non-magnetic conductors, and low loss (α≪β), which covers nearly all practical RF and microwave coax.

2. Coaxial line geometry and notation

Coaxial line cross-section Cross-section of a coaxial line showing the center conductor of outside diameter d, the dielectric with relative permittivity epsilon r and loss tangent tan delta, and the outer conductor with inside diameter D. D d Dielectric: εr, tan δ Outer conductor: σ Center conductor: σ
Figure 1. Coaxial cross-section. d=2a is the center-conductor outside diameter; D=2b is the outer-conductor inside diameter.
SymbolMeaningUnits
d=2aOutside diameter of the center conductorm
D=2bInside diameter of the outer conductorm
εrRelative permittivity of the dielectric fill—
tan⁡δDielectric loss tangent—
σConductor conductivityS/m
fOperating frequencyHz
cSpeed of light in vacuum, 299 792 458m/s
μ0Permeability of free space, ≈4π×10−7H/m
η0Impedance of free space, μ0c≈376.73Ω

3. Worked example: inputs

The example line is a semi-rigid, SMA-size coax: a 0.050-inch (1.27 mm) copper center conductor inside a 4.20 mm bore, filled with solid PTFE. It is analyzed at 10 GHz.

InputValueNotes
Center conductor diameter, d1.27 mmRadius a=0.635 mm
Outer conductor inside diameter, D4.20 mmRadius b=2.10 mm; D/d=3.307
Relative permittivity, εr2.1Solid PTFE
Loss tangent, tan⁡δ0.0002Typical PTFE at microwave frequencies
Conductivity, σ5.8 × 107 S/mAnnealed copper, both conductors
Frequency, f10 GHz

4. Step-by-step analysis

1Enter the conductor geometry

Open the Coax TEM Mode Calculator and enter the center-conductor outside diameter d=1.27 mm and the outer-conductor inside diameter D=4.20 mm. Confirm the unit selection matches the values typed. Only the ratio D/d sets the impedance, but the absolute size sets the TE1,1 cutoff and the conductor loss, so both diameters matter.

Equation 1Dd=4.20mm1.27mm=3.307D/d = 4.20 mm / 1.27 mm = 3.307

2Enter the dielectric properties

Enter εr=2.1 and tan⁡δ=0.0002 for PTFE. The permittivity controls impedance, wavelength, velocity, and cutoff; the loss tangent controls only the dielectric attenuation. For air-spaced lines use εr=1.0 and tan⁡δ=0.

3Enter the conductor conductivity

Enter σ=5.8×107 S/m for copper. The calculator uses it to find the surface resistance and conductor loss. Plating matters: if the center pin is silver- or gold-plated, use the conductivity of the plating, provided the plating is several skin depths thick at the operating frequency (see the Skin Depth Calculator).

4Enter the frequency and run the calculation

Enter f=10 GHz and calculate. The free-space wavelength at this frequency, used in several of the steps below, is:

Equation 2λ0=cf=2.9979×10810×109=29.98mmλ_0 = c / f = 2.9979×10^8 / (10×10^9) = 29.98 mm

5Read the characteristic impedance, Z0

For the TEM mode, the characteristic impedance depends only on the diameter ratio and the dielectric:

Equation 3Z0=η02πεrln⁡(Dd)≈59.96εrln⁡(Dd)ΩZ_0 = η_0 / (2π·√ε_r) · ln(D/d) ≈ (59.96 / √ε_r) · ln(D/d) ΩPozar [1], §2.2; Ramo, Whinnery & Van Duzer [3]
Equation 4Z0=59.962.1ln⁡(3.307)=41.38×1.196=49.49ΩZ_0 = (59.96 / √2.1) · ln(3.307) = 41.38 × 1.196 = 49.49 Ω
Result: Z0=49.49Ω, within 1.1% of a 50 Ω system.

The same geometry gives the per-unit-length inductance and capacitance, useful for circuit models:

Equation 5L′=μ02πln⁡(Dd)=239.2nH/m,C′=2πε0εrln⁡(D/d)=97.68pF/mL′ = (μ_0 / 2π) · ln(D/d) = 239.2 nH/m; C′ = 2π·ε_0·ε_r / ln(D/d) = 97.68 pF/mPozar [1], §2.1; Collin [2]

As a check, L′/C′=49.49Ω.

6Check the TE1,1 cutoff frequency

The TEM mode propagates at any frequency, but above the cutoff of the first higher-order mode, TE1,1, energy can couple into a non-TEM field pattern and cause resonances and impedance errors. The widely used approximation sets the TE1,1 cutoff wavelength in the dielectric equal to the mean circumference of the line:

Equation 6λc≈π(a+b)εr⟹fcTE11≈cπ(a+b)εr=2cπ(D+d)εrλ_c ≈ π·(a + b)·√ε_r ⟹ f_c,TE11 ≈ c / (π·(a + b)·√ε_r) = 2c / (π·(D + d)·√ε_r)Pozar [1], §3.5; Marcuvitz [5], §2.4
Equation 7fc=2(2.9979×108)π(5.47×10−3)2.1=24.08GHzf_c = 2·(2.9979×10^8) / (π·(5.47×10^−3)·√2.1) = 24.08 GHz
Result: fcTE11=24.08 GHz. At 10 GHz, f/fc=0.42, so the line is safely single-mode TEM.
Design margin: many designers keep the highest operating frequency at or below about 90–95% of the computed TE1,1 cutoff to allow for dimensional tolerances, the approximation's error (a few percent for typical 50 Ω ratios), and discontinuities such as connectors and bends. The exact cutoff comes from the root of a Bessel-function equation [5], [6].

7Read the guide wavelength, λg

Because the TEM mode has no cutoff, the guide wavelength is simply the free-space wavelength scaled by the dielectric:

Equation 8λg=cfεr=λ0εr=29.98mm1.449=20.69mmλ_g = c / (f·√ε_r) = λ_0 / √ε_r = 29.98 mm / 1.449 = 20.69 mmPozar [1], §2.1; Collin [2]
Result: λg=20.69 mm. A quarter-wave section of this line at 10 GHz is 5.17 mm long.

8Read the propagation constant, γ=α+jβ

The phase constant gives the phase shift per unit length:

Equation 9β=2πλg=2πfεrc=2π0.02069m=303.7rad/mβ = 2π / λ_g = 2π·f·√ε_r / c = 2π / 0.02069 m = 303.7 rad/mPozar [1], §2.1

That is 17 402°/m, or about 17.4° per millimeter of line at 10 GHz. Combining β with the total attenuation from Step 10:

Result: γ=0.1164+j303.7m−1.

9Read the phase and group velocities

For TEM propagation in a non-dispersive dielectric, phase and group velocity are equal and independent of frequency:

Equation 10vp=ωβ=cεr,vg=(dβdω)−1=cεrv_p = ω / β = c / √ε_r; v_g = (dβ/dω)^−1 = c / √ε_rPozar [1], §2.1; Ramo, Whinnery & Van Duzer [3]
Equation 11vp=vg=2.9979×1082.1=2.069×108m/s,VF=vpc=1εr=0.690v_p = v_g = 2.9979×10^8 / √2.1 = 2.069×10^8 m/s; VF = v_p / c = 1 / √ε_r = 0.690
Result: vp=vg=2.069×108 m/s; velocity factor 0.690; time delay 4.83 ns/m.

This equality is a key difference from hollow-waveguide modes, where vp>c, vg<c, and both change rapidly near cutoff (compare the Circular Waveguide Calculator).

10Read the attenuation constant

Conductor loss. First find the surface resistance and skin depth of the metal:

Equation 12Rs=πfμ0σ=π(1010)(4π×10−7)5.8×107=0.02609Ω,δs=1πfμ0σ=0.661μmR_s = √(π·f·μ_0 / σ) = √(π·(10^10)·(4π×10^−7) / (5.8×10^7)) = 0.02609 Ω; δ_s = 1 / √(π·f·μ_0·σ) = 0.661 μmPozar [1], §1.7; Ramo, Whinnery & Van Duzer [3]

Then, with η=η0/εr=260.0Ω, so 2ηln⁡(b/a)=621.9Ω, 1/a=1575m−1 and 1/b=476.2m−1:

Equation 13αc=Rs2ηln⁡(b/a)(1a+1b)=0.02609621.9(1575+476.2)=0.0860Np/mα_c = R_s / (2η·ln(b/a)) · (1/a + 1/b) = (0.02609 / 621.9) · (1575 + 476.2) = 0.0860 Np/mPozar [1], §2.7 (Example 2.6) and §3.4; Collin [2]

Dielectric loss. For any TEM line:

Equation 14αd=ktan⁡δ2=πfεrtan⁡δc=π(1010)(1.449)(0.0002)2.9979×108=0.0304Np/mα_d = k·tanδ / 2 = π·f·√ε_r·tanδ / c = π·(10^10)·(1.449)·(0.0002) / (2.9979×10^8) = 0.0304 Np/mPozar [1], §3.1

Total loss and conversion to decibels (1 Np = 8.686 dB):

Equation 15α=αc+αd=0.1164Np/m=1.011dB/mα = α_c + α_d = 0.1164 Np/m = 1.011 dB/m
Result: αc=0.747 dB/m, αd=0.264 dB/m, total α=1.011 dB/m (about 30.8 dB per 100 ft).
Interpretation: conductor loss dominates here (74% of the total). Because αc∝f and αd∝f, dielectric loss takes a larger share as frequency rises. The ideal smooth-conductor result is a lower bound; surface roughness, plating, and connector interfaces add loss in real assemblies.

5. Results summary table

SMA-size PTFE coax: d=1.27 mm, D=4.20 mm, εr=2.1, tan⁡δ=0.0002, σ=5.8×107 S/m, f=10 GHz.

Calculator outputEquationValue
TE1,1 cutoff frequency2c / (π·(D + d)·√ε_r)24.08 GHz
Characteristic impedance(η_0 / (2π·√ε_r))·ln(D/d)49.49 Ω
Guide wavelengthc / (f·√ε_r)20.69 mm
Phase constant2π·f·√ε_r / c303.7 rad/m
Propagation constantα + jβ0.1164 + j303.7 m⁻¹
Phase velocityc / √ε_r2.069 × 10⁸ m/s
Group velocityc / √ε_r2.069 × 10⁸ m/s
Conductor attenuationR_s·(1/a + 1/b) / (2η·ln(b/a))0.0860 Np/m (0.747 dB/m)
Dielectric attenuationπ·f·√ε_r·tanδ / c0.0304 Np/m (0.264 dB/m)
Total attenuationα_c + α_d0.1164 Np/m (1.011 dB/m)

6. Using the calculator for design

Finding the diameter ratio for a target impedance

Inverting the impedance equation gives the required ratio directly:

Equation 16Dd=exp⁡(Z0εr59.96)D/d = exp(Z_0·√ε_r / 59.96)
Target Z0DielectricεrRequired D/d
50 ΩAir1.002.302
50 ΩPTFE2.103.348
50 ΩSolid polyethylene2.253.493

In practice, pick the nearest standard wire or tube size for one conductor, compute the other from the ratio, then enter both into the calculator to confirm Z0 and check the TE1,1 cutoff against the highest operating frequency.

A practical workflow

  1. Choose the dielectric from mechanical, thermal, and loss requirements.
  2. Compute D/d for the target impedance.
  3. Size the line so the TE1,1 cutoff sits above the highest operating frequency with margin. Higher frequencies force smaller lines, which is why millimeter-wave coax and connectors are physically small.
  4. Check the attenuation at the highest frequency. A smaller line raises αc, so cutoff and loss pull in opposite directions.
  5. Use λg and β to size stubs, quarter-wave transformers, and phase-matched lengths.

7. Common input mistakes

  • Using the outer jacket diameter for D. D is the inside diameter of the outer conductor (equal to the dielectric outside diameter), not the cable's overall diameter.
  • Mixing radii and diameters. The impedance ratio is the same either way, but the TE1,1 cutoff and conductor loss will be off by a factor of two if radii are entered where diameters are expected.
  • Unit mismatches. Confirm mm, inches, and GHz selections before reading results.
  • Using foamed-dielectric permittivity for solid PTFE (or vice versa). Foamed dielectrics have an effective εr well below the solid value; use the manufacturer's velocity factor to back out εr,eff=1/VF2.
  • Operating near TE1,1 cutoff. The approximation and tolerances both introduce error; leave margin.

8. References

  1. D. M. Pozar, Microwave Engineering, 4th ed. Hoboken, NJ: John Wiley & Sons, 2012. Ch. 1 (surface resistance, skin depth), Ch. 2 (TEM transmission line parameters, coax L′, C′, Z0, conductor loss), Ch. 3 (TEM dielectric loss, coaxial line higher-order modes and TE11 cutoff approximation).
  2. R. E. Collin, Foundations for Microwave Engineering, 2nd ed. New York: IEEE Press / Wiley, 2001. Ch. 3 (TEM transmission lines and coaxial line attenuation).
  3. S. Ramo, J. R. Whinnery, and T. Van Duzer, Fields and Waves in Communication Electronics, 3rd ed. New York: John Wiley & Sons, 1994. Chs. 5 and 8 (transmission lines, coaxial line fields, skin effect).
  4. C. A. Balanis, Advanced Engineering Electromagnetics, 2nd ed. Hoboken, NJ: John Wiley & Sons, 2012. Ch. 9 (coaxial line TEM, TE and TM modes).
  5. N. Marcuvitz, Waveguide Handbook, MIT Radiation Laboratory Series, vol. 10. New York: McGraw-Hill, 1951; reprinted London: IEE / Peter Peregrinus, 1986. §2.4 (coaxial waveguide modes and cutoff wavelengths).
  6. S. A. Schelkunoff, Electromagnetic Waves. New York: D. Van Nostrand, 1943. (Coaxial line higher-order mode cutoffs.)
  7. E. Tiesinga, P. J. Mohr, D. B. Newell, and B. N. Taylor, “CODATA recommended values of the fundamental physical constants: 2018,” Rev. Mod. Phys., vol. 93, 025010, 2021. (Values of c, μ0, ε0.)

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© 2026 SiberSci, LLC. Equations are given for low-loss lines with non-magnetic materials and smooth conductors. Numerical values in the worked example were computed with c=299792458 m/s and μ0=4π×10−7 H/m.

Finally, SiberSci, LLC also provides visitors with access to Electromagnetic Engineering Calculators that are used for designing circuits, or exploring solutions to problems.  Four transmission line calculators are provided that include a Circular Waveguide Calculator, Coax TEM Mode Calculator, a Rectangular Waveguide TEm,n Calculator, and to complete this set a Rectangular Waveguide TMm,n Calculator.  The remaining three Electromagnetic Engineering Calculators are general purpose analysis tools.  For instance, the Wavelength Calculator can be used to determine the length of a Monopole Antenna, while the Skin Depth Calculator is commonly used to determine the metal thickness for Microstrip, Stripline, and CPW transmission lines.  The Skin Depth Calculator is also used to determine the metal thickness for electroplating cavity assemblies and waveguide assemblies.  The final calculator is the Dielectric Heating Calculator, which is used to estimate the frequency-dependent power and electric field to heat a defined volume and mass of dielectric material in a defined time period.  If you do not see the calculator that you need for your problem, then Contact Us to determine if we can provide you with this calculator.

If you need help with your Coax TEM Mode Calculator design problem, send us a message.

Coax TEM Mode Calculator FAQ

What does the SiberSci Coax TEM Mode Calculator compute?

From the coaxial line's dimensions and material properties, it computes seven quantities: the TE11 higher-order mode cutoff frequency, TEM characteristic impedance, guide wavelength, propagation constant, phase velocity, group velocity, and attenuation constant from metal (conductor) and dielectric loss. It was developed by Dr. Scott Best of SiberSci, LLC for RF and microwave transmission line design.

How do you calculate the characteristic impedance of a coaxial cable?

Characteristic impedance of a coaxial line is Z0 = (η0 / 2π√εr)·ln(D/d) ≈ (59.96 / √εr)·ln(D/d) ohms, where D is the inside diameter of the outer conductor, d is the outside diameter of the center conductor, and εr is the dielectric's relative permittivity. Example: d = 1.27 mm, D = 4.20 mm, PTFE (εr = 2.1) gives Z0 ≈ 49.5 Ω, close to a standard SMA line.

What D/d ratio gives a 50 ohm coaxial line?

Solve Z0 = (59.96/√εr)·ln(D/d) for D/d = exp(Z0·√εr / 59.96). For 50 Ω, an air-dielectric line needs D/d ≈ 2.30, a PTFE line (εr = 2.1) needs D/d ≈ 3.35, and a solid polyethylene line (εr ≈ 2.25) needs D/d ≈ 3.49. Use the calculator to iterate dimensions against standard tube and wire sizes.

What is the maximum frequency of a coaxial cable?

A coaxial line is limited by the onset of the TE11 mode, whose cutoff is approximately fc ≈ 2c / (π·(D + d)·√εr). Above that frequency, energy can couple into a non-TEM mode and cause resonances and impedance errors. For the PTFE-filled 4.20 mm / 1.27 mm example, TE11 cutoff is about 24 GHz. Smaller coax and lower-εr dielectrics push this limit higher, which is why millimeter-wave connectors are physically tiny.

Why is 50 ohms the standard impedance for coaxial cable?

50 Ω is a compromise between two optima for air-dielectric coax: minimum conductor attenuation occurs at about 77 Ω (D/d ≈ 3.59), and maximum power handling before voltage breakdown occurs at about 30 Ω (D/d ≈ 1.65). 50 Ω sits between them, giving good loss and power performance, and became the RF test and measurement standard. 75 Ω, near the low-loss optimum, is common in video and cable TV systems where power is low.

What is the velocity factor of a coaxial cable?

Velocity factor is the propagation speed relative to the speed of light: VF = 1/√εr for a TEM line with a non-magnetic dielectric. Solid PTFE gives VF ≈ 0.69, solid polyethylene ≈ 0.66, and foamed or air-spaced dielectrics typically 0.80 to 0.90 or higher. The calculator reports phase velocity directly, which is needed for cutting phase-matched cables and delay lines to length.

Are phase velocity and group velocity the same in coaxial cable?

For the TEM mode in a lossless coaxial line with a non-dispersive dielectric, phase velocity and group velocity are equal (v = c/√εr) and independent of frequency, so pulses travel without dispersion. This is a key difference from waveguide modes, where phase velocity exceeds c, group velocity is below c, and both vary strongly near cutoff. In real cables, small differences arise from conductor skin effect and frequency-dependent dielectric properties.

How do you calculate the guide wavelength in a coaxial line?

In TEM mode, guide wavelength is λg = c / (f·√εr), the free-space wavelength divided by √εr. At 1 GHz in PTFE-filled coax, λg ≈ 207 mm, so a quarter-wave stub is about 52 mm long. Guide wavelength is used to size quarter-wave transformers, stubs, baluns, and phase-shifting sections.

How is attenuation calculated for a coaxial line?

Total attenuation is the sum of conductor and dielectric loss. Conductor loss is αc = Rs·(1/a + 1/b) / (2η·ln(b/a)) Np/m, where a and b are the inner and outer radii, η = η0/√εr, and Rs = √(πfμ0/σ) is the surface resistance. Dielectric loss is αd = π·f·√εr·tanδ / c Np/m. Multiply Np/m by 8.686 for dB/m. Conductor loss grows with √f and dielectric loss grows with f, so dielectric loss dominates at high frequencies.

What is the propagation constant of a coaxial transmission line?

The propagation constant is γ = α + jβ, where α is the attenuation constant (Np/m) and β = 2πf√εr/c is the phase constant (rad/m). β determines phase shift per unit length and α determines amplitude decay. Together they describe how a signal changes along the line and are the inputs needed for ABCD or S-parameter models of coaxial sections.

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